Author Topic: Mystery grandmother to find anyone up to a challenge?  (Read 686 times)

Online panda40

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Re: Mystery grandmother to find anyone up to a challenge?
« Reply #9 on: Saturday 02 December 17 16:48 GMT (UK) »
Thanks Maureen for that lead I will spend the evening following that route to see if I can get the pieces to fit. I love a mystery.
Regards
Panda
Chapman. Kent/Liverpool 1900+
Linnett.Kent/liverpool 1900+
Button. Kent
Sawyer. Kent
Swain. Kent
Austin/en. Kent
Ellen. Kent
Harman. Kent/ norfolk

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Offline MaureeninNY

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Re: Mystery grandmother to find anyone up to a challenge?
« Reply #10 on: Saturday 02 December 17 16:54 GMT (UK) »
It fits,trust me. :) :) :) ;)

I'll let you do the work,though.

Maureen

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Online panda40

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Re: Mystery grandmother to find anyone up to a challenge?
« Reply #11 on: Saturday 02 December 17 19:14 GMT (UK) »
So here is the answer to the mystery
Sarah Corker was born in 1843 to William and Nancy Corker
She married Samuel Mills in 1860
Samuel died and she married John Hill in 1873
Louisa Mills is from her first marriage
Louisa married Walter Anderson in 1882
Their son is on the 1911census with Sarah Hill listed as his grandmother.
Now if only all of my mysteries were as easy as this one to solve.
Regards
Panda
Chapman. Kent/Liverpool 1900+
Linnett.Kent/liverpool 1900+
Button. Kent
Sawyer. Kent
Swain. Kent
Austin/en. Kent
Ellen. Kent
Harman. Kent/ norfolk

Offline MaureeninNY

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Re: Mystery grandmother to find anyone up to a challenge?
« Reply #12 on: Saturday 02 December 17 20:28 GMT (UK) »
 ;D ;D ;D

Maureen

Offline ThrelfallYorky

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Re: Mystery grandmother to find anyone up to a challenge?
« Reply #13 on: Sunday 03 December 17 14:50 GMT (UK) »
Well done!
Threlfall (Southport), Isherwood (lancs & Canada), Newbould + Topliss(Derby), Keating & Cummins (Ireland + lancs), Fisher, Strong& Casson (all Cumberland) & Downie & Bowie, Linlithgow area Scotland . Also interested in Leigh& Burrows,(Lancashire) Griffiths (Shropshire & lancs), Leaver (Lancs/Yorks) & Anderson(Cumberland and very elusive)